How to calculate the current throwing through a resistor given the potential difference and resistance?
- Saturday Nov 28,2009 02:58 AM
- By diddy
- In Others
The potential difference across a resistor is 4.4 ‘ 10^2 V. If the resistance of the resistor is 1.8 kW how much current flows through the resistor?
I am really trying to understand how to answer this more than just answer this. I would greatly appreciate a clear explanation.
Current, Kw, Potential Difference, Resistance, Resistor
3 Comments
If I may expand:
The Resistance R is defined as the Quotient of Voltage (or Potential Difference) and Current over an electronic component:
R = U / I
The Power P that flows through this component is being calculated as:
P = U*I
This is a matter of definition: "The volt is defined as the value of the voltage across a conductor when a current of one ampere dissipates one watt of power in the conductor."
Therefore: P = U * I = U²/R = (4.4*10^2 V)^2/1.8*10^3 ? = 1.1*10^3 W
As Vince has pointed out, the unit for Resistance is the Ohm (?).
Resistance is expressed in kohm not kWatts
Watts are units of power….
V = R.I where I is current…
I = V/R = 4.4×10^2 V / 1800 ohms = ……..
V = I * R
V = 4.4 * 10^2 volts
R = 1.8* 10^3 ohms
I = ??
Formula
I = V/R
I = 4.4* 10^2/1.8*10^3
I = 0.244 amps.
Recent Posts
Recent Comments
Leave a reply